Angels outfielder Mike Trout today was named a recipient of a 2019 Louisville Slugger Silver Slugger™ Award which is given to the best offensive players at each position in both the American and National Leagues. The award is Trout's seventh honor in eight full seasons and the 24th overall for the Angels.

With today's announcement, Trout extends his franchise record with seven Silver Sluggers. He broke Vladimir Guerrero's previous Club record of four (2004-07) after capturing his fifth award in 2016. Trout is the sixth outfielder to receive the honors seven times at any point in his career, joining: Barry Bonds (12), Manny Ramirez (8), Ken Griffey Jr. (7), Vladimir Guerrero (7) and Tony Gwynn (7). Trout also joins Alex Rodriguez as the only players to win the award seven times by their age-27 season.

The New Jersey native finished his ninth big league season (eighth full year) with the Angels, batting .291 with 27 doubles, two triples, 45 home runs, 104 RBI, 11 stolen bases, 110 walks and 110 runs scored. He led the league in both OBP (.438) and slugging percentage (.645) and joined Ty Cobb and Mickey Mantle as the only center fielders to lead their league in both categories in multiple seasons (Trout also led in 2017). Additionally, he became the first player in A.L. history to have 25+ HR and 10+ stolen bases in eight consecutive seasons. Trout will receive his Award during an on-field ceremony early in the 2020 season.

The Silver Slugger Award winners were determined by a vote of Major League Baseball coaches and managers who named the players they felt were the best offensive producers at each position in both the American and National Leagues in 2019. Selections were based on a combination of offensive statistics, including batting average, on-base percentage and slugging percentage, as well as the coaches' and managers' general impressions of a player's overall offensive value. Managers and coaches were not allowed to vote for players on their own teams.